A `50 Hz AC` source of `20 V` is connected across `R ` and `C` as shown in figureure.

The voltage across `R` is `12 V`. The voltage across `C` is

Options

A. 8 V
B. 16 V
C. 10 V
D. not possible to determine unless values of R and C are given

Answer

B

Explanation

`v=50 Hz, V=20 V, V_(R)=12 V`
In case of RC circuit, `V=sqrt(V_(R)^(2)+V_(C)^(2))`
`rArr" "(20)^(2)=(12)^(2)+(V_(C))^(2)`
`rArr" "(V_(C))^(2)=400-144=256 rArr V_(C)=16 V.`