When a ball is thrown up vertically with velocity `v_0`, it reaches a maximum height of h. If one wishes to triple the maximum height then the ball should be thrown with velocity

Options

A. `sqrt(3)v_(0)`
B. `3 v_(0)`
C. `9 v_(0)`
D. `3//2 v_(0)`

Answer

A

Explanation

As `v^(2)=u^(2)+2as`
`therefore" "u^(2) prop " ….(i)"`
For given condition, `u^(2) prop 3s" …..(ii)"`
From eqn. (i) and (ii), `(u^(2))/(u^(2))=3 rArr u' =sqrt(3)v_(0)`.