If the temperature of a black body incresese from `7^(@)C` to `287^(@)C` then the rate of energy radiation increases by

Options

A. `((287)/(7))^(4)`
B. 16
C. 4
D. 2

Answer

B

Explanation

The energy radiated per unit time by a black body at absolute temperature T is given by `H = A sigma T^(4)`.
where A is the area of a black body
or `(H')/(H)=([(287+273)K]^(4))/([(7+273)K]^(4))=[(560)/(280)]^(4)=16`