A large horizontal surface moves up and down in SHM with an amplitude of 1 cm . If a mass of 10 kg (which is placed on the surface) is to remain continually in contact with it, the maximum frequency of S.H.M. will be

Options

A. 5 Hz
B. 0.5 Hz
C. 1.5 Hz
D. 10 Hz

Answer

A

Explanation

Here, a =1 cm = 0.01 m, The mass will remain in contact with surface, if
`mg=m omega^(2)a` or `omega = sqrt(g//a)`
or `2pi upsilon = sqrt(g//a)` or `upsilon =(1)/(2pi)sqrt((g)/(a))`
`upsilon =(7)/(2xx22)sqrt((980)/(1))=4.9 s^(-1)=5 Hz`