The correct order of dipole moment is :

Options

A. `CH_4 le NF_3 lt NH_3 lt H_2O`
B. `NF_3 lt CH_4lt NH_3 lt H_2 O`
C. `NH_3 lt NF_3 lt CH_4 lt H_2O`
D. `H_2O lt NH_3 lt CH_4 lt NF_3`

Answer

A

Explanation

In `H_(2)O` , electronegativity difference is highest . So , dipole moment is highest in this . `CH_(4)` is a symmertical tetrahedral structure and its dipole moment is zero .