A body is projected horizontally with a velocity of `4sqrt2m//sec`. The velocity of the body after 0.7 seconds will be bearly (Take g = `10 m/sec^(2)`)

Options

A. 10 m/sec
B. 9 m/sec
C. 19 m/sec
D. 11 m/sec

Answer

B

Explanation

After 0.7 sec the horizontal velocity component of the body `=4sqrt2m//sec` since there is no change in velocity in horizontal direction.
The vertical velocity component after 0.7 seconds
`=0+"gt" = 0+0.7xx10`
= 7 m/sec
`therefore" resultant velocity of the body"=sqrt((4sqrt2)^(2)+7^(2))`
`=sqrt(32+49)="9m/sec"`