What is the energy stored in the capacitor between terminals a and b of the network shown in the figure ? (Capacitance of each capacitance `C=1muF`)

Options

A. `12.5muJ`
B. Zero
C. `25muJ`
D. `50muJ`

Answer

A

Explanation

Network is redrawn as shown in figure.

This is a balanced Wheatstone's network.
Equivalent capacitance `C_(eq)=C`
Charge on capacitor between the terminals a and b
`(Q)/(2)=(CV)/(2)`
Energy stored in the capacitor
`=(1((Q)/(2))^(2))/(2C)=(Q^(2))/(8C)=(C^(2)V^(2))/(8C)=(CV^(2))/(8)`
Given : `C=1 muF, V=10V`
`=((1xx10^(-6))xx10^(2))/(8)`
`=(100)/(8)xx10^(-6)=12.5muJ`