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A ball is suspended by a thread of lengt...

A ball is suspended by a thread of length l at the point O on an incline wall as shown. The inclination of the wall with the vertical is α.The thread is displaced through a small angle β away from the vertical and the ball is released. Find the period of oscillation of pendulum.
Consider both cases
a. `alpha gt beta`
b. `alpha lt beta`
Assuming that any impact between the wall and the ball is elastic.

A

`sqrt((L)/(g))[pi+2sin^(-1).(alpha)/(beta)]`

B

`sqrt((L)/(g))[pi-2sin^(-1).(beta)/(alpha)]`

C

`sqrt((L)/(g))[2sin^(-1).(beta)/(alpha)-pi]`

D

`sqrt((L)/(g))[2sin^(-1).(alpha)/(beta)+pi]`

Text Solution

Verified by Experts

The correct Answer is:
A

`theta=theta_(0)sin omega t" "omega=sqrt((g)/(L))`
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