A radioacitve nucleus is being produced at a constant rate `alpha` per second. Its decay constant is `lambda`. If `N_(0)` are the number of nuclei at time `t=0`, then maximum number of nuceli possible are .

Options

A. `N_(0)+(alpha)/(lambda)`
B. `N_(0)`
C. `(lambda)/(alpha)+N_(0)`
D. `(alpha)/(lambda)`

Answer

D

Explanation

Maximum number of nuclei will be present, when rate of decay = rate of formation
`lambda. N=alpha, N=(alpha)/(lambda)`