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In a concave mirror, an object is placed...

In a concave mirror, an object is placed at a distance `d_1` from the focus and the real image is formed aat a distance `d_2` from the focus. Then the focal length of the mirror is :

A

`sqrt(d_(1)d_(2))`

B

`d_(1)d_(2)`

C

`(d_(1)+d_(2))//2`

D

`sqrt((d_(1)//d_(2)))`

Text Solution

Verified by Experts

The correct Answer is:
A

Using `(1)/(v)+(1)/(u)=(1)/(f)`
Given `u=f+d_(1)" "v=f+d_(2)`
`f=(uv)/(u+v)=((f-d_(1))(f+d_(2)))/((f+d_(1))+(f+d_(2)))`
On solving `f=sqrt(d_(1)d_(2))`
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