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A short linear object of length b lies a...

A short linear object of length b lies along the axis of a concave mirror or focal length f at a distance u from the pole of the mirror. The size of the image is approximately equal to

A

`(lf)/(d-f)`

B

`(d-f)/(lf)`

C

`l(f^(2))/((d-f)^(2))`

D

`((d-f)^(2))/(f^(2))l`

Text Solution

Verified by Experts

The correct Answer is:
C

Use `(1)/(v)+(1)/(u)=(1)/(f)`
Find `v_(1)`, when u = d and `v_(2)`, when `u=d+l`
Size of image `=v_(1)-v_(2)=l((f)/(d-f))^(2)`
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