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2 phenylethylbromide when heated with Na...

2 phenylethylbromide when heated with NaOEt, elimination takes place. No deuterium exchange takes place when the reaction is carried out in `C_(2)H_(5)OD` solvent. The mechanism will be

A

E1 elimination

B

E2 elimination

C

E1cB elimination

D

E2 or E1cB

Text Solution

Verified by Experts

The correct Answer is:
B

It is a primary bromide. So it will undergo elimination either by E2 or E1cB. Since there is no deuterium exchange in `C_(2)H_(5)OD` solvent, `C-H` bond is not broken to form carbanion. Hence the actual mechanism is E2 only.
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