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For the electrochemical cell, (M)|M^(+))...

For the electrochemical cell, `(M)|M^(+))||(X^(-)|X)`.
`E^(@)(M^(+)//M)=0.44V` and `E^(@)(X//X^(-))=0.33V`.
From this data one can deduce that

A

` M + X to M^ ( + ) + X^ ( -) ` is the sponthaneous reaction

B

`M^(+)+X^(-)to M+X` is the spontaneous reaction

C

`E_("cell")=0.77V`

D

`E_("cell)=-0.77V`

Text Solution

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The correct Answer is:
B

`M^(+)+X to M+X` is spontaneous because for the cell represented by `M|M'||X|X`, the value of `E^(@)` is positive i.e. (0.44-0.33)V=0.11V
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For the electrochemical cell (M|M^(+))|| (X^(-)|X) E^(@) (M^(+)//M) = 0.44V and E^(@) (X//X^(-))=0.33V From this data one can deduce that :

If E^(@)(M^(+)/M)= -0.44V and E^(@)(X/X^(-)) = 0.33V . From this data one can conclude that:

For the electrochemical cell, M|M^(+) ||X^(-)|X , E_(M^(+)//M)^(@) = 0.44 V and E_(X//X^(-))^(@) = 0.33 V . From this data we can deduce that :

For the electrochemicl cell, M|M^(+)||X^(-)|X E_((M^(+)//M))^(@) = 0.44 V and E_((X//X^(-)))^(@) = 0.33 V From this data one can deduce that :

For the electrochemical cell, (M|M^(o+))||(X^(c-)|X) , E^(c-)._((M^(o+)|M))=0.44V , and E^(c-)._((X|X^(c-))=-0.33V . From this data, one can conclude that

For the electrochemical cell, (M|M^(o+))||(X^(c-)|X),E^(c-)._((M^(o+)|M))=0.44V and E^(c-)._((X|X^(c-)))=0.334V

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