A gang capacitor is formed by interlocking a number of plates as shown in figure. The distance between the consecutive plates is 0.885 cm annd the overlapping area of the plates is 5 `cm^(2)`. The capacity of the unit is

Options

A. 1.06 pF
B. 4 pF
C. 6.36 pF
D. 12.72 pF

Answer

B

Explanation

The given arrangement of nine plates is equivalent to the parallel combination of 8 capacitors.
the capacity of each capacitor,
`C=(epsi_(0)A)/(d)`
`=(8.854xx10^(-12)xx5xx10^(-4))/(0.885xx10^(-2))=0.5pF`
Hence, the capacity of 8 capacitors.
`=8C=8xx0.5=4pF`