`200 MeV` of energy may be obtained per fission of `U^235`. A reactor is generating `1000 kW` of power. The rate of nuclear fission in the reactor is.

Options

A. 1000
B. `2xx10^(8)`
C. `3.125xx10^(16)`
D. 931

Answer

C

Explanation

Energy`=200MeV`
`=200xx16xx10^(-19)xx10^(6)`
`=200xx1.6xx10^(-13)`
power P=1000 kW
`=1000xx10^(3)W`
Rate of dismitegration=`("Power")/("energy")`
`=(10^(6))/(200xx1.6xx10^(-13))`
`=3.125xx10^(16)` per second