An ideal coil of `10` henry is joined in series with a resistance of `5` ohm and a battery of `5` volt. `2` second after joining, the current flowing in ampere in the circuit will be

Options

A. `e^(-1)`
B. `(1-e^(-1))`
C. `(1-e)`
D. `e`

Answer

B

Explanation

Given, `L=10H,R=5Omega,E=5V`
and t=2s
current R-L circuit
`I=I_(0)(1-e^(-Rt//L))`
`I=(E)/(R)(1-e^(-Rt//L))`
`=(5)/(5)(1-E^(-5XX2//10))` ltBRgt `I=(1-e^(-1))`