The diameter of the objective of the telescope is `0.1` metre and wavelength of light is `6000 Å`. Its resolving power would be approximately

Options

A. `6xx10^(-5)rad`
B. `6xx10^(4)`rad
C. `6xx10^(-3)`rad
D. `6xx10^(-6)` rad

Answer

D

Explanation

Resolving power of telescope
`=(1.22lamda)/(d)`
d=diamter of objet lens=0.1m
and `lamda=6000xx10^(-10)`
`therefore`Resolving power`=(1.22xx6000xx10^(-10))/(0.1)`
`=7.32xx10^(-6)`
`~~6xx10^(-6)` radians approximately.