The magnetic field at P on the axis of a solenoid having 100 turn/m and carrrying a currennt of 5A is

Options

A. `250mu_(0)`
B. `500sqrt(2)mu_(0)`
C. `500mu_(0)`
D. `250sqrt(2)mu_(0)`

Answer

D

Explanation

The magnetic field at P is
`B=(mu_(0)nI)/(2)(costheta+costheta)`
where n is number of turns, I the current, given, n=100,I=5A and `theta=45^(@)`
`B=(mu_(0)xx100xx5)/(2)xx(2)/(sqrt(2))`
`impliesB=250sqrt(2)mu_(0)`