The wavelength of a spectral line emmited by hydrogen atom in the lyman series is `16/15R` cm. what is the value of `n_(2)`

Options

A. 2
B. 3
C. 4
D. 1

Answer

C

Explanation

For lymann series,
`(1)/(lamda)=R[(1)/(1^(2))-(1)/(n_(2)^(2))]`
`(15R)/(16)=R[(1)/(1^(2))-(1)/(n_(2)^(2))]`
`(15R)/(16R)=[(n_(2)^(2)-1)/(n_(2)^(2))]`
`(15)/(16)=(n_(2)^(2)-1)/(n_(2)^(2))`
`15n_(2)^(2)=16n_(2)^(2)-16`
`n_(2)^(2)=16`
`n_(2)=4`