A schematic plot of In `K_(eq)` versus inverse o ftemperature for a reaction is shown below

the reaction must be:

Options

A. highly spontaneous at ordinary temperature
B. one with negligible enthalpy change
C. endothermic
D. exothermic

Answer

D

Explanation

Variation of `K_(eq)` with temperature T is given by van'g hoff equation.
`"log "K_(eq)=-(DeltaH^(@))/(2.303RT)+(DeltaS^(@))/(R)`
Slope of the given line is positive indicating that term A is positive thus `DeltaH^(@)` is negative Thus, reactionn is exothermic.