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When 45gm solution is dissolved in 600gm...

When `45gm` solution is dissolved in `600gm`water freezing point lower by `2.2K`,calcuate molar mass of solute `(K_(f)=1.86 "kg mol"^(-1))`

A

63.4gm

B

80gm

C

90gm

D

21gm

Text Solution

Verified by Experts

The correct Answer is:
A
`m_(1)=600g" "DeltaT_(f)=2.2k`
`m_(2)=45g" "k_(f)=1.86"K kg mol"^-1`
`M=(k_(1)xxm_(2))/(DeltaT_(f)xxm_(1))=(1.86xx2.2k)/(2.2xx0.6)=63.4"g mol"^(-1)`
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