Home
Class 12
CHEMISTRY
When NH(3)(0.1 M) 50 ml mix with HCl (0....

When `NH_(3)(0.1 M) 50 ml` mix with `HCl (0.1 M) 10 ml` then what is `pH` of resultant solution (`pK_(b)=4.75)`

A

9.25

B

10

C

9.85

D

4.15

Text Solution

Verified by Experts

The correct Answer is:
A
`NH_(3)+HCl to NH_(4)Cl`
`"Initial "underset("5 mmol")(50xx0.1)" "underset("1mmol")(10xx0.1)`
`"Rem 4mmol "0" ""1mmol"`
`pOH=pk_(b)+log""("salt")/("base")`
`=4.75+log""(1)/(4)=4.15`
`=pH=14-pOH=14-4.15=9.85`
Promotional Banner

Topper's Solved these Questions

  • AIIMS 2017

    AIIMS PREVIOUS YEAR PAPERS|Exercise CHEMISTRY|52 Videos

  • AIIMS 2018 PAPER 2

    AIIMS PREVIOUS YEAR PAPERS|Exercise CHEMISTRY|45 Videos

Similar Questions

Explore conceptually related problems

100 ml of 0.15 M HCl is mixed with 100 ml of 0.05 M HCl, is the pH of the resulting solution?

Aniline behaves as a weak base. When 0.1 M, 50 mL solution of aniline was mixed with 0.1 M , 25mL solution of HCl the pH of resulting solution was 8. The the pH of 0.01 M solution of anilinium chloride will be (K_w =10^(-14))

10 ml of M/10 NH_(4)OH is mixed with 4ml of M/10H_(2)SO_(4) solution. The pH of the resulting solution is (pK_(b)NH_(4)OH=4.76), (log2=0.3) .

5 mL of 0.4 N NaOH is mixed with 20 mL of 0.1 N HCl. The pH of the resulting solution will be

20 mL of 0.5 M HCl is mixed with 30 mL of 0.3 M HCl, the molarity of the resulting solution is :

100 ml of 0.1 M CH_(3)COOH are mixed with 100ml of 0.1 M NaOH , the pH of the resulting solution would be

100 mL solution (I) of buffer containin 0.1 (M) HA and 0.2 (M) A^- , is mixed with another solution (II) of 100 mL containing 0.2 (M) HA and 0.3 (M) A^- . After mixing, what is the pH of resulting solution ? [Given: pK_a of HA=5]

50 mL of 0.1 M HCl and 50 mL of 2.0 M NaOH are mixed. The pH of the resulting solution is

200 mL of 0.4M solution of CH_(3)COONa is mixed with 400 mL of 0.2 M solution of CH_(3)COOH . After complete mixing, 400 mL of 0.1 M NaCl is added to it. What is the pH of the resulting solution? [K_(a) of CH_(3)COOH=10^(-5)]