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Rate of two reaction whose rate constant...

Rate of two reaction whose rate constants are`k_(1)& k_(2)` are equal at 300 k such that: So caculate `n(A_(2))/(A_(1))=?" "Ea_(2)=Ea_(1)=2RT.`

A

ln4

B

2

C

log 2

D

2-ln2

Text Solution

Verified by Experts

The correct Answer is:
B
In presence of catalyst :
`log""(K_(2))/(K_(1))=log ""(A_(2))/(A_(1))+(Ea_(2)-Ea_(1))/(2.3RT)`
` log 1=log""(A_(2))/(A_(1))-(2RT)/(2.3RT)ln""(A_(2))/(A_(1))=2,`
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