In vanderwaal equation at const temperat...

In vanderwaal equation at const temperature 300 `K, a=14 atm "lt"^(2)"mole"^(2),v=100 ml, n=1` mole, what is pressure of gas:

42 atm

210 atm

500 atm

106 atm

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The correct Answer is:

`(P+(an^(2))/(V^(2)))(V)=nRT`
`(P+(1.4)/((0.1)^(2)))(0.1)=1xx0.082xx3600`
`(P+140)xx0.1=4.6`
`0.1 P+14=246`
`0.1 P =10.6`
`P=106` atm

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