The velocity v and displacement x of a particle executing simple harmonic motion are related as
`v (dv)/(dx)= -omega^2 x`.
`At x=0, v=v_0.` Find the velocity v when the displacement becomes x.

Options

A. `v=sqrt(v_(0)^(2)+omega^(2)x^(2))`
B. `v=sqrt(v_(0)^(2)-omega^(2)x^(2))`
C. `v=3sqrt(v_(0)^(3)+omega^(3)x^(3))`
D. `v=v_(0)-(omega^(3)x^(3)e^(x^(3)))^(1//3)`

Answer

B