A force F=(10+0.5 x) acts on a particle ...

A force `F=(10+0.5 x)` acts on a particle in the x-direction. What would be the work done by this force during a displacement from `x=0` to `x=2m` (F is in newton and x in metre)

A

25 J

B

29 J

C

21 J

D

18 J

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The correct Answer is:

C

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