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A conductivity cell has a cell constant ...

A conductivity cell has a cell constant of `0.5 cm^(-1)`. This cell when filled with 0.01 M NaCl solution has a resistance of 384 ohms at `25^(@)C`. Calculate the equivalent conductance of the given solution.

A

`130.2 Omega^(-1) cm^(2) (g eq)^(-1)`

B

`137.4 Omega^(-1) cm^(2) (g eq)^(-1)`

C

`154.6 Omega^(-1) cm^(2) (g eq)^(-1)`

D

`169.2 Omega^(-1) cm^(2) (g eq)^(-1)`

Text Solution

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The correct Answer is:
A
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