How far will a body free-fall in 1 second If released from rest ?

Options

A. 0.0 m
B. 4.9 m
C. 9.8 m
D. 19.6 m.

Answer

B

Explanation

Use `x=v_0+1//2at^2`
where x = distance of fall, `v_0`=initial velocity =0 , a=acceleration , 9.8 `m//sec^2`, and t=1 second
`x=0+1//2at^2`
`x=(1//2)(9.8)(1)^2`
x=4.9 m