using the illustration when both surfaces 1 and 2 are exposed to the atmoshere, `P_1` and `P_2` are gauge pressure , and `h_1` and `h_2` are heights .

The Bernoulli equation for this situation is `h_1+P_1 /W+V_1^2/"2a"=h_2+P_2/W+V_2^2/"2a"`
The velocity of the fluid leavening point (2) is constant and can be expressed as

Options

A. `V_2=(P_1//P_2)V_1`
B. `V_2=(P_1//P_2 ) a h `
C. `V_2=[(h_1-h_2)(2a)]^(1//2)`
D. none of the above

Answer

C

Explanation

`h_1+P_1/W+V_1^2/(2a)+h_2+P_2/W+(V_2^2)/(2a)` at 1 the velocity in all practical purposes =0 and `P_0=P_2=0` then the equation above can be written as
`h_2+V_2^2/(2a)=h_1`
`V_2^2=(h_1-h_2)2a`
`V_2=[(h_1-h_2)(2a)]^(1//2)`