The particle accelerated at a constat rate from 23 mi./br. to 58 mi./hr. In 3.5 sec. Its acceleration was

Options

A. 10 mi./hr. per sec.
B. 58 mi./hr. per sec.
C. 23 mi./hr. per sec.
D. less than 10 mi./hr. per sec.

Answer

A

Explanation

`a=(v_2-v_1)/t`
`=(58 mi//hr-23 mi//hr )/(3.5 sec)="3.5 mi/hr"/"3.5 sec"`
=10 mi./hr per sec
Or since 35 mi/hr = 51 ft/sec
`a="51 ft/sec"/"3.5 sec"`
=12.7 ft. per `sec^2`