Since speed changed at a uniform rate and the average velocity is equal to the average of the Initial and final speeds. how far has the particle traveled while It was accelerating ?

Options

A. 51 ft
B. 600ft
C. 210ft
D. less than 20 mi.

Answer

C

Explanation

`v=(v_1+v_2)/2`
v=1/2(23+58) mi/hr . V=40.5 mi/hr
v=40.5 x `"5280 ft./min."/"3600 sec./hr."` =59.41 ft/sec.
X=59.4 ft./sec. x 3.5 sec X =208 ft .