A negative iodoform test (i.e., no yellow precipitate ) will be the result when NaOH + `I_2` is reacted with

Options

A. `CH_3-CH_2-CH_2-oversetoversetH|C=O`
B. `H-oversetoverset(O)(||)C-CH_3`
C. `CH_3-undersetunderset(O)(||)C-CH_2-CH_3`
D. `CH_3-undersetunderset(OH)|C-CH_3`

Answer

A

Explanation

A yellow precipitate of iodoform is produced in the reaction with methyl ketones, alcohols that may be oxidized to methyl ketones, or acetaldehyde.