In the network given below all the five capacitors have the same capacitance C each . Then the capacitance between the terminal A and B will be

Options

A. `C/5`
B. `5C`
C. C
D. `5/2` C

Answer

C

Explanation

Here `C_1` and `C_2` are in series . Similarly `C_3` and `C_4` are also in series . This whole setup is in parallel.

So, C=`C_2+C_2`
`(C+C)/2="2C"/2+C`
Here, no current will follow the `C_5` path because it is null point circuit