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The [OH] in a solution is 1xx10^(8) . Th...

The [OH] in a solution is `1xx10^(8)` . The pH of the solution is

A

`10.0`

B

`8.0`

C

`6.0`

D

`4.0`

Text Solution

Verified by Experts

The correct Answer is:
B

pOH=-log `[OH^-]=-log 1 xx 10^(-8)=8`
pH+pOH=14
`therefore ` pH=14-8=6
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