Given the enthalpy of formation of `CO_(2)(g)` is -94.0 KJ, of CaO(s) is -152 KJ, and the enthalpy of the reaction `CaCO_(3)(s) rarr CaO(s)+CO_(2)(g)` is 42KJ, the enthalpy of formation of `CaCO_(3) (s)` is

Options

A. `-288` kJ
B. `+202` kJ
C. `-202` kJ
D. `-42 ` kJ

Answer

A

Explanation

The enthalpy of formation of `CaCO_3(s)` =Enthalpy of formation of CaO(s)+Enthalpy of formation of `CO_2(g)`-Enthalpy of the reaction `CaCO_3(s) to CaO (s) + CO_2(g)` =-152 kJ - 14.0 kJ-(42kJ)=-288 kJ