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If s and S are respectiveluy solubility ...

If s and S are respectiveluy solubility and solubility product of a sparingly soluble binary electrolyte , then :

A

`s=S^(1//2)`

B

`s=1//2S`

C

s=S

D

`s=S^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`S=s^(2) :. S=sqrt(5)` for electrolytes like AgCl, AgBr or AB type .
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