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The correct relation is...

The correct relation is

A

`DeltaG-RT" ln "K//Q`

B

`DeltaG=+RT" ln "K`

C

`DeltaG=-RT" ln "Q//K`

D

`DeltaG=+RT" ln "Q`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaG=DeltaG^(@)+RT" ln "Q`
`DeltaG=-RT" ln"(K)/(Q)`
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