The hybridisation and magnetic behaviour of complex `[Ni(CO)_(4)]` is:

Options

A. `dsp^(2)`, paramagnetic
B. `dsp^(2)`, diamagnetic
C. `sp^(3)`, paramagnetic
D. `sp^(3)`,diamagnetic

Answer

D

Explanation

`[Ni(CO)_(4)]`
`x+4(0)=0`
`x=0`
O, No. of Ni is zero
`Ni=[Ar]3d^(8)4s^(2)4p^(0)`

CO is a strong field ligand so 4s.
electron shift into 3d.

And no. of unpaired e-=0
So it has diamagnetic nature.