In a transformer number of turns in primary circuit is 500 and in secondary circuit number of turns is 10 and load resistance to 10 `Omega` and voltage of secondary coil is 50 V then find the current in primary circuit .

Options

A. 0.2A
B. 0.3A
C. 0.4A
D. 0.1A

Answer

D

Explanation

`i_(2)=(V_(2))/(R_(L))=(50)/(10)=5A`
`(i_(1))/(i_(2))=(N_(2))/(N_(1)) rArr (i_(1))/(5) =(10)/(500) rArr i_(1)=0.1A`