If two protons are moving with speed `v=4.5 xx 10^(5)m//s` parallel to each other then find the ratio of electrostatic and magnetic force between them : -

Options

A. `4.4xx10^(5)`
B. `2.2xx10^(5)`
C. `3.3xx 10^(5)`
D. `1.1xx10^(5)`

Answer

A

Explanation

`F_(E ) =(ke^(2))/(r^(2))`
`F_(M)=eVB=e.V.(mu_(0))/(4pi).(eV)/(r^(2))`
`(F_(E))/(F_(M)) =((ke^(2))/(r^(2)))/((e^(2)V^(2).mu_(0))/(4pir^(2)))=(k.4pi)/( V^(2).mu_(0))`
`=(9xx10^(9)xx4pi)/(4.5xx4.5xx10^(10)xx4pi xx 10^(-7)) = (9xx10^(6))/( 4.5xx4.5) =4.4xx10^(5)`