A transformer consists of 500 turn in primary coil and 10 turns in secondary coilk with the load of `10 Omega ` Find out current in the primary coil when the voltage across secondary coil 50V.

Options

A. 0.3A
B. 0.1A
C. 0.5A
D. 0.7A

Answer

B

Explanation

`(V_(P))/(V_(S)) =(N_(P))/(N_(S)) rArr (V_(1))/(50)=(500)/(10)`
`V_(1)=2500`
`i_(s) =(V_(s))/(R )=(50)/(10) =5A`
`(i_(P))/(i_(s))=(V_(s))/(V_(P))`
`(i_(P))/(5)=(50)/(2500) rArr i_(P)=0.1A`