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Ph-CH(2)-CH=CH-CH(3) overset((i)Br(2))un...

`Ph-CH_(2)-CH=CH-CH_(3) overset((i)Br_(2))underset((ii)Alc.KOH)to`

A

`Ph-CH=CH-CH=CH_(2)`

B

`Ph-CH_(2)-underset(OH)underset(|)(CH)-underset(OH)underset(|)(CH)-CH_(3)`

C

`Ph-CH_(2)-C-=C-CH_(3)`

D

`Ph-C-=C-CH_(2)-CH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
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