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Calculate the binding energy per nucleon...

Calculate the binding energy per nucleon (B.E./nucleon) in the nuclei of `._(26)Fe^(56)`. Given :
`mp[._(26)Fe^(56)]=55.934939 " amu",m[._(0)n^(1)]=1.00865 " amu" , m[._(1)"II"^(1)]=1.00782 " amu"`

A

477.45 MeV

B

8.52 MeV

C

577 MeV

D

10.52 MeV

Text Solution

Verified by Experts

The correct Answer is:
B

`BE=[26mp+30mm-m^(56)Fe]c^(2)`
`m_(n)=1.00866u`
`m_(p)=1.00727u`
`BE=[26xx1.00727+30xx1.00866-55.936]xx931` ltBrgt `=0.51282xx931`
`=0.477.437MeV`
`"Binding energy per nucleon "=(477.435)/(56)"MeV"="8.52 MeV"`
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