A transformer consists of 500 turn in primary coil and 10 turns in secondary coil with the load of `10Omega.` Find out current in the primary coil when the voltage across secondary coil is 50 V.

Options

A. 5A
B. .1A
C. 10A
D. 2A

Answer

B

Explanation

`(V_(P))/(V_(s))=(N_(P))/(N_(S))`
`(V_(P))/(V_(S))=(500)/(10)`
`V_(P)=2500`
`i_(s)=(V_(S))/(R)=(50)/(10)=5A`
`i_(s)=(V_(S))/(R)=(50)/(10)=5A`
`(i_(p))/(i_(s))=(v_(S))/(v_(P))`
`(i_(p))/(5)=(500)/(2500)`
`i_(p)=(1)/(5)xx5=1A`