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Distance of 5^("th") dark fringe from ce...

Distance of `5^("th")` dark fringe from centre is 4 mm. If D = 2 m, `lambda=600` nm, then distance between slits is :

A

1.35 mm

B

2.00 mm

C

3.25 mm

D

10.35 mm

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The correct Answer is:
A
Distance of `5^("th")` dark
Fringe from centre `=(9beta)/(2)`
`(9xx lambda xx D)/(2xxd)=4xx10^(-3)" "rArr" "d=(9xx6xx10^(-7)xx2)/(2xx4xx10^(-3))=1.35mm`
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