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A bulb is emitted electromagnetic radiat...

A bulb is emitted electromagnetic radiation of 660 nm wave length. The Total energy of radiation is 3 x `10^(-18) J `The number of emitted photon will be : `(h=6.6xx10^(-34)J xx s, C=3xx10^(8)m//s)`

A

1

B

10

C

100

D

1000

Text Solution

Verified by Experts

The correct Answer is:
B
Number of photons = n
`E=(hc)/(lambda)`
`3xx10^(-18)-(6.6xx10^(-34)xx3xx10^(8)xxn)/(660xx10^(-9))`
`n=(30)/(3)=10`
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