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For a wire R/l = 1/2 and length of wire ...

For a wire `R/l = 1/2` and length of wire is `l = 5` cm . If potential differrence of 1V is applied across it current through wire will be : (R = Resistance)

A

40 A

B

4A

C

25 A

D

2.5 A

Text Solution

Verified by Experts

The correct Answer is:
A
`R = l/2 Omega = (5xx10^(-2))/(2)Omega`
`i=V/R = 1/(5xx10^(-2)) xx2 = 40A`
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