A coil is placed in y-z plane making an angle of `30^(@)` with x-axis . The current through coil is I, and number of turns are N. If a magnetic field of strength 'B' is applied in positive x-direction, then find the torque experienced by coil: (Radius of coil is R)
`(N = 100, I = 1A, r = 2m , B = 1/pi T)`

Options

A. `100 N-m`
B. `50 N-m`
C. `200 N-m`
D. `150 N-m`

Answer

C

Explanation

NI `(vecA xx vecB)`
`(vectau) = NIABsin theta(theta = 30^(@))`
`= NI.piR^(2).Bsin 30^(@)`
`= (piNIR^(2)B)/(2) N-m`
`= (pi xx 100 xx 1 xx (2)^(2))/(2) 1/pi`
`=200 N-m`