A sample which has half life of `10^(33)` year . If initial number of nuclei of the sample is `26 xx 10^(24)`. Then find out of the number of nuclei decayed in 1 year.

Options

A. `1.82 xx10^(-7)`
B. `182 xx 10^(-7)`
C. `18.2 xx 10^(-7)`
D. `1820 xx 10^(-7)`

Answer

C

Explanation

`-(dN)/(dt) = lambdaN`
`-dN = (ln2)/(T) xx N xx dt`
`= (0.7)/(10^(33)) xx 26 xx 10^(24) xx 1`
`- dN = 0.7 xx 26 xx 10^(-7) = 18.2 xx 10^(-7)`