Tranformer `rarr` ideal `rarr E_(P) = 1000 V, I_(P) = 50 A`
`200 V rarr 80` houses
Resistance of secondary coild will be :

Options

A. `2 Omega`
B. `3 Omega`
C. `1 Omega`
D. `4 Omega`

Answer

C

Explanation

`P_("in") = P_("out")`
`E_(P)I_(P) = (V_(s)^(2))/(R_(s))`
`1000 xx 50 = (220^(2))/(R_(s))`
`R_(s) = (22^(2))/(10xx50) = 0.968 Omega ~~ 1 Omega`.